Altair Posted August 30, 2004 at 11:09 PM Report Posted August 30, 2004 at 11:09 PM I have read some books on the Japanese abacus (算盘) and know the basics of how to do calculations. Each rod of the Japanese abacuses I own have four unit-beads and one five-bead. I also own a Chinese abacus, which has five unit-beads and two five-beads on each rod. I can do calculations on the Chinese abacus based on the methods I learned for the Japanese abacus; however, I cannot figure out a use for the fifth unit-bead or the second five-unit bead. If I use complementary numbers to do addition and subtraction, I would never use all five unit-beads to form the number five or both of the five-beads to from the number ten. Using all the beads on the rod to form the number 15 would be completely out of the question. I found an excellent site (http://members.aol.com/chineseabacus/to_teacher.html) that talks about the Chinese abacus, but it does not explain uses for the extra beads. Can anyone help with an explanation? Quote
Claw Posted August 30, 2004 at 11:40 PM Report Posted August 30, 2004 at 11:40 PM The extra unit-bead and five-bead are redundant. Technically speaking, if there was ever the case where you move all 5 unit-beads down, you would move them back up and move down one five-bead. Similarly, if you move all 2 five-beads down, you would move them back up and move down a unit-bead in the next column. I guess this is useful for visualization of how the numbers are carried over, but the extra steps could be skipped once you know the rules. So the extra unit- and five-bead aren't really all that necessary in practice. Quote
Altair Posted September 2, 2004 at 12:04 AM Author Report Posted September 2, 2004 at 12:04 AM Thanks for the explanation. This makes sense. I have considered introducing my kids to the abacus and your response gives me the idea that the extra beeds might be helpful in teaching which numbers are complementary to which. Quote
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